Integrand size = 20, antiderivative size = 49 \[ \int \frac {a+b \log \left (c \left (d+e x^m\right )^n\right )}{x} \, dx=\frac {\log \left (-\frac {e x^m}{d}\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{m}+\frac {b n \operatorname {PolyLog}\left (2,1+\frac {e x^m}{d}\right )}{m} \]
[Out]
Time = 0.04 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {2504, 2441, 2352} \[ \int \frac {a+b \log \left (c \left (d+e x^m\right )^n\right )}{x} \, dx=\frac {\log \left (-\frac {e x^m}{d}\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{m}+\frac {b n \operatorname {PolyLog}\left (2,\frac {e x^m}{d}+1\right )}{m} \]
[In]
[Out]
Rule 2352
Rule 2441
Rule 2504
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {a+b \log \left (c (d+e x)^n\right )}{x} \, dx,x,x^m\right )}{m} \\ & = \frac {\log \left (-\frac {e x^m}{d}\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{m}-\frac {(b e n) \text {Subst}\left (\int \frac {\log \left (-\frac {e x}{d}\right )}{d+e x} \, dx,x,x^m\right )}{m} \\ & = \frac {\log \left (-\frac {e x^m}{d}\right ) \left (a+b \log \left (c \left (d+e x^m\right )^n\right )\right )}{m}+\frac {b n \text {Li}_2\left (1+\frac {e x^m}{d}\right )}{m} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.00 \[ \int \frac {a+b \log \left (c \left (d+e x^m\right )^n\right )}{x} \, dx=a \log (x)+\frac {b \left (\log \left (-\frac {e x^m}{d}\right ) \log \left (c \left (d+e x^m\right )^n\right )+n \operatorname {PolyLog}\left (2,\frac {d+e x^m}{d}\right )\right )}{m} \]
[In]
[Out]
Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 2.14 (sec) , antiderivative size = 180, normalized size of antiderivative = 3.67
method | result | size |
risch | \(b \ln \left (x \right ) \ln \left (\left (d +e \,x^{m}\right )^{n}\right )+\left (\frac {i b \pi \,\operatorname {csgn}\left (i \left (d +e \,x^{m}\right )^{n}\right ) {\operatorname {csgn}\left (i c \left (d +e \,x^{m}\right )^{n}\right )}^{2}}{2}-\frac {i b \pi \,\operatorname {csgn}\left (i \left (d +e \,x^{m}\right )^{n}\right ) \operatorname {csgn}\left (i c \left (d +e \,x^{m}\right )^{n}\right ) \operatorname {csgn}\left (i c \right )}{2}-\frac {i b \pi {\operatorname {csgn}\left (i c \left (d +e \,x^{m}\right )^{n}\right )}^{3}}{2}+\frac {i b \pi {\operatorname {csgn}\left (i c \left (d +e \,x^{m}\right )^{n}\right )}^{2} \operatorname {csgn}\left (i c \right )}{2}+b \ln \left (c \right )+a \right ) \ln \left (x \right )-\frac {b n \operatorname {dilog}\left (\frac {d +e \,x^{m}}{d}\right )}{m}-b n \ln \left (x \right ) \ln \left (\frac {d +e \,x^{m}}{d}\right )\) | \(180\) |
[In]
[Out]
none
Time = 0.31 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.41 \[ \int \frac {a+b \log \left (c \left (d+e x^m\right )^n\right )}{x} \, dx=\frac {b m n \log \left (e x^{m} + d\right ) \log \left (x\right ) - b m n \log \left (x\right ) \log \left (\frac {e x^{m} + d}{d}\right ) - b n {\rm Li}_2\left (-\frac {e x^{m} + d}{d} + 1\right ) + {\left (b m \log \left (c\right ) + a m\right )} \log \left (x\right )}{m} \]
[In]
[Out]
\[ \int \frac {a+b \log \left (c \left (d+e x^m\right )^n\right )}{x} \, dx=\int \frac {a + b \log {\left (c \left (d + e x^{m}\right )^{n} \right )}}{x}\, dx \]
[In]
[Out]
\[ \int \frac {a+b \log \left (c \left (d+e x^m\right )^n\right )}{x} \, dx=\int { \frac {b \log \left ({\left (e x^{m} + d\right )}^{n} c\right ) + a}{x} \,d x } \]
[In]
[Out]
\[ \int \frac {a+b \log \left (c \left (d+e x^m\right )^n\right )}{x} \, dx=\int { \frac {b \log \left ({\left (e x^{m} + d\right )}^{n} c\right ) + a}{x} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {a+b \log \left (c \left (d+e x^m\right )^n\right )}{x} \, dx=\int \frac {a+b\,\ln \left (c\,{\left (d+e\,x^m\right )}^n\right )}{x} \,d x \]
[In]
[Out]